#
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# contributor license agreements. See the NOTICE file distributed with
# this work for additional information regarding copyright ownership.
# The ASF licenses this file to You under the Apache License, Version 2.0
# (the "License"); you may not use this file except in compliance with
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# http://www.apache.org/licenses/LICENSE-2.0
#
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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#
"""
MLflow-related functions to load models and apply them to pandas-on-Spark dataframes.
"""
from typing import List, Union # noqa: F401 (SPARK-34943)
from pyspark.sql.types import DataType
import pandas as pd
import numpy as np
from typing import Any
from pyspark.pandas._typing import Label, Dtype # noqa: F401 (SPARK-34943)
from pyspark.pandas.utils import lazy_property, default_session
from pyspark.pandas.frame import DataFrame
from pyspark.pandas.series import Series, first_series
from pyspark.pandas.typedef import as_spark_type
__all__ = ["PythonModelWrapper", "load_model"]
[docs]class PythonModelWrapper(object):
"""
A wrapper around MLflow's Python object model.
This wrapper acts as a predictor on pandas-on-Spark
"""
def __init__(self, model_uri: str, return_type_hint: Union[str, type, Dtype]):
self._model_uri = model_uri
self._return_type_hint = return_type_hint
@lazy_property
def _return_type(self) -> DataType:
hint = self._return_type_hint
# The logic is simple for now, because it corresponds to the default
# case: continuous predictions
# TODO: do something smarter, for example when there is a sklearn.Classifier (it should
# return an integer or a categorical)
# We can do the same for pytorch/tensorflow/keras models by looking at the output types.
# However, this is probably better done in mlflow than here.
if hint == "infer" or not hint:
hint = np.float64
return as_spark_type(hint)
@lazy_property
def _model(self) -> Any:
"""
The return object has to follow the API of mlflow.pyfunc.PythonModel.
"""
from mlflow import pyfunc
return pyfunc.load_model(model_uri=self._model_uri)
@lazy_property
def _model_udf(self) -> Any:
from mlflow import pyfunc
spark = default_session()
return pyfunc.spark_udf(spark, model_uri=self._model_uri, result_type=self._return_type)
def __str__(self) -> str:
return "PythonModelWrapper({})".format(str(self._model))
def __repr__(self) -> str:
return "PythonModelWrapper({})".format(repr(self._model))
def predict(self, data: Union[DataFrame, pd.DataFrame]) -> Union[Series, pd.Series]:
"""
Returns a prediction on the data.
If the data is a pandas-on-Spark DataFrame, the return is a pandas-on-Spark Series.
If the data is a pandas Dataframe, the return is the expected output of the underlying
pyfunc object (typically a pandas Series or a numpy array).
"""
if isinstance(data, pd.DataFrame):
return self._model.predict(data)
elif isinstance(data, DataFrame):
return_col = self._model_udf(*data._internal.data_spark_columns)
# TODO: the columns should be named according to the mlflow spec
# However, this is only possible with spark >= 3.0
# s = F.struct(*data.columns)
# return_col = self._model_udf(s)
column_labels = [
(col,) for col in data._internal.spark_frame.select(return_col).columns
] # type: List[Label]
internal = data._internal.copy(
column_labels=column_labels, data_spark_columns=[return_col], data_fields=None
)
return first_series(DataFrame(internal))
else:
raise ValueError("unknown data type: {}".format(type(data).__name__))
[docs]def load_model(
model_uri: str, predict_type: Union[str, type, Dtype] = "infer"
) -> PythonModelWrapper:
"""
Loads an MLflow model into an wrapper that can be used both for pandas and pandas-on-Spark
DataFrame.
Parameters
----------
model_uri : str
URI pointing to the model. See MLflow documentation for more details.
predict_type : a python basic type, a numpy basic type, a Spark type or 'infer'.
This is the return type that is expected when calling the predict function of the model.
If 'infer' is specified, the wrapper will attempt to determine automatically the return type
based on the model type.
Returns
-------
PythonModelWrapper
A wrapper around MLflow PythonModel objects. This wrapper is expected to adhere to the
interface of mlflow.pyfunc.PythonModel.
Examples
--------
Here is a full example that creates a model with scikit-learn and saves the model with
MLflow. The model is then loaded as a predictor that can be applied on a pandas-on-Spark
Dataframe.
We first initialize our MLflow environment:
>>> from mlflow.tracking import MlflowClient, set_tracking_uri
>>> import mlflow.sklearn
>>> from tempfile import mkdtemp
>>> d = mkdtemp("pandas_on_spark_mlflow")
>>> set_tracking_uri("file:%s"%d)
>>> client = MlflowClient()
>>> exp = mlflow.create_experiment("my_experiment")
>>> mlflow.set_experiment("my_experiment")
We aim at learning this numerical function using a simple linear regressor.
>>> from sklearn.linear_model import LinearRegression
>>> train = pd.DataFrame({"x1": np.arange(8), "x2": np.arange(8)**2,
... "y": np.log(2 + np.arange(8))})
>>> train_x = train[["x1", "x2"]]
>>> train_y = train[["y"]]
>>> with mlflow.start_run():
... lr = LinearRegression()
... lr.fit(train_x, train_y)
... mlflow.sklearn.log_model(lr, "model")
LinearRegression(...)
Now that our model is logged using MLflow, we load it back and apply it on a pandas-on-Spark
dataframe:
>>> from pyspark.pandas.mlflow import load_model
>>> run_info = client.list_run_infos(exp)[-1]
>>> model = load_model("runs:/{run_id}/model".format(run_id=run_info.run_uuid))
>>> prediction_df = ps.DataFrame({"x1": [2.0], "x2": [4.0]})
>>> prediction_df["prediction"] = model.predict(prediction_df)
>>> prediction_df
x1 x2 prediction
0 2.0 4.0 1.355551
The model also works on pandas DataFrames as expected:
>>> model.predict(prediction_df[["x1", "x2"]].to_pandas())
array([[1.35555142]])
Notes
-----
Currently, the model prediction can only be merged back with the existing dataframe.
Other columns have to be manually joined.
For example, this code will not work:
>>> df = ps.DataFrame({"x1": [2.0], "x2": [3.0], "z": [-1]})
>>> features = df[["x1", "x2"]]
>>> y = model.predict(features)
>>> # Works:
>>> features["y"] = y # doctest: +SKIP
>>> # Will fail with a message about dataframes not aligned.
>>> df["y"] = y # doctest: +SKIP
A current workaround is to use the .merge() function, using the feature values
as merging keys.
>>> features['y'] = y
>>> everything = df.merge(features, on=['x1', 'x2'])
>>> everything
x1 x2 z y
0 2.0 3.0 -1 1.376932
"""
return PythonModelWrapper(model_uri, predict_type)
def _test() -> None:
import os
import doctest
import sys
from pyspark.sql import SparkSession
import pyspark.pandas.mlflow
os.chdir(os.environ["SPARK_HOME"])
globs = pyspark.pandas.mlflow.__dict__.copy()
globs["ps"] = pyspark.pandas
spark = (
SparkSession.builder.master("local[4]").appName("pyspark.pandas.mlflow tests").getOrCreate()
)
(failure_count, test_count) = doctest.testmod(
pyspark.pandas.mlflow,
globs=globs,
optionflags=doctest.ELLIPSIS | doctest.NORMALIZE_WHITESPACE,
)
spark.stop()
if failure_count:
sys.exit(-1)
if __name__ == "__main__":
try:
import mlflow # noqa: F401
import sklearn # noqa: F401
_test()
except ImportError:
pass